Problem Solutions For Introductory Nuclear Physics By Kenneth S. Krane ●
| Pitfall | Typical Mistake | Correction | | :--- | :--- | :--- | | | Using atomic mass in the semi-empirical mass formula, forgetting to subtract Z electron masses. | Remember: (M_\textnucleus = M_\textatom - Z m_e + B_e/c^2) (electron binding energy is small but non-zero). | | Q-value sign | Writing (Q = (M_\textinitial - M_\textfinal)c^2) as (M_\textfinal - M_\textinitial). | Exothermic (spontaneous) decay has (Q>0). Endothermic reactions require (Q<0). | | Angular momentum in gamma decay | Assuming all gamma decays are dipole. | Check the spin-parity change: (\Delta l = 1) is dipole, (\Delta l = 2) is quadrupole, etc. Parity change determines E vs. M. | | Natural units confusion | Using (\hbar = 1) then forgetting to reinsert it for numerical answers. | Work symbolically, then plug in (\hbar c = 197.3 \text MeV·fm) at the end. |
The $\pi^0$ decays into two photons: $\pi^0 \rightarrow \gamma + \gamma$. The mass of the $\pi^0$ is $m_\pic^2 = 135$ MeV. | Pitfall | Typical Mistake | Correction |
You have found a solution for Krane’s problem 6.15 (the deuteron photodisintegration). Now what? | Exothermic (spontaneous) decay has (Q>0)
Kenneth Krane's Introductory Nuclear Physics is a staple in university courses, highly regarded for its comprehensive and accessible approach. The book is structured to progressively build your knowledge: | Check the spin-parity change: (\Delta l =
Model the deuteron as a particle in a finite square well potential. Show that the depth ( ) and range ( ) are just enough to bind one -state.